Find the value of each of the following quantities. (a) C(5, 4)
(b) C(5, 0)
(c) P(5, 1)
(d) P(5, 5)

(a) 5   (b)1      (c)5    (d)120

Step-by-step explanation:

Formula for combinations:

Formula for permutations:

(a) C(5, 4)  =

(b) C(5, 0) =

(c) P(5, 1)  =

(d) P(5, 5)  =   [as 0!=1]

Hence, the required answer is

(a) 5   (b)1      (c)5    (d)120

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.