Please Solve this, it would be extremely helpful for me.

In the figure given below,

AB ll EF ll CD. If AB = 22.5 cm,

EP = 7.5 cm, PC =15 cm and

DC = 27 cm. Calculate:

(i) EF (ii) AC

Step-by-step explanation:

1) ΔCPD & ΔEPF

∠CPD = ∠EPF   { Vertically opposite angles}

∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}

ΔCPD ≈ΔEPF  {AA criteria for similarity }

Cross multiply

EF * 15 = 27 * 7.5

EF = 27 * 0.5

EF = 13.5 cm

ii) EF // AB, so Triangles ACB & ECF are similar triangles

AC = 37.5 cm

answer: i don't understand it

step-by-step explanation: sorry

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you