Olcquations Week 5 Assignment: Mixture Problems and Systems of Equations
Due Sunday by 11:59pm
Points 10
Submitting an external tool
Solve interest applications using a system of equations
Question
Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4%
interest on the total investment. How much money did he put in each account?
Sorry, that's incorrect. Try again?
3% amount: S 600
8% amount: S 2400
FEEDBACK
VIEW ANSWER
SUBMIT
port
Top
Content attribution

Step-by-step explanation:

You have the right numbers, but the wrong accounts.

__

Let x represent the amount invested at 8% (the highest rate). Then the total interest is ...

  .08x +.03(3000 -x) = .04(3000)

  .05x = .01(3000) . . . . subtract .03(3000)

  x = 3000/5 = 600

Matthew invested $600 at 8%, $2400 at 3%.

Comment on checking your answer

You may notice that the overall interest rate is 4%, closer to 3% than to 8%. That means more of the money must be invested at 3% than at 8%.

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3