(2.05 MC) Triangle PQR is transformed to Triangle P'Q'R'. Triangle PQR has vertices P(4,0), Q(0,-4) and R(-8,-4). Triangle P'Q'R' has vertices P'(1,0), Q'(0,-1), and R'(-2,-1). Part A: What is the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' Part B: Write The Coords of triangle P"Q"R" obtained after P'Q'R' is reflected about the y-axis Part C: Are the two Triangles PQR and P"Q"R" congruent?

(A) The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R'  is 1/4

(B) Coordinates of Δ P"Q"R"

P" (-1,0)

Q"(0,-1)

R"(2,-1)

(C) Triangles PQR and P"Q"R" are not congruent.

Given

ΔPQR is transformed into ΔP'Q'R'

Coordinates of P, Q, R are

P (4,0),

Q(0,-4)

R(-8,-4)

Coordinates of P'Q'R' are

P'(1,0)

Q'(0,-1)

R'(-2,-1)

(A) By Distance formula we can find the distance between P Q and P'Q'

Distance formula =

Where D = Distance between two points

from distance formula we can write that

PQ =

Similarly

P'Q'=

PQ /P'Q' = 4

hence the scale factor of dilation is 1/4 (Compression)

(B )The Coordinates of Reflection about y axis can be written for a point

So the Coordinated of Δ P"Q"R" can be written as

P" (-1,0)

Q"(0,-1)

R"(2,-1)

(C) ΔPQR  and ΔP"Q"R" are similar triangles but they are not  congruent because their sides  are not equal in size.

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Part A: The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4

Part B:

P''(-1, 0)

Q''(0, -1)

R''(2, -1)

Part C:

The two Triangles PQR and P''Q''R'' are not congruent

Step-by-step explanation:

The coordinates of triangle PQR are;

P(4, 0)

Q(0, 4)

R(-8, -4)

The coordinates of triangle P'Q'R' are;

P'(1, 0)

Q'(0, -1)

R'(-2, -1)

Part A:

The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' can be found from the ratio of the respective coordinates as follows;

The ratio of the x, and y coordinates of the points are;

P'/P  = x'/x = 1/4, y'/y =0/0

R'/R = x'/x = -2/-8 = 1/4, y'/y =-1/-4 = 1/4

Therefore, the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' = 1/4

Part B: For reflection across the y-axis, we have;

Pre-image (x, y) becomes the image, (-x, y)

Therefore, we have;

Reflection of P'(1, 0) about the y-xis becomes P''(-1, 0)

Reflection of Q'(0, -1) about the y-xis becomes Q''(0, -1)

Reflection of R'(-2, -1) about the y-xis becomes R''(2, -1)

Part C:

The two Triangles PQR and P''Q''R'' are similar but they are not congruent as the dimensions of PQR are larger than the dimensions of the sides of triangle P''Q''R''.