What is the volume of a gas at 253K if the gas occupies 50.0 mL at a temp of 273K? Provided pressure is held constant.

V₂ = 46.34 mL

Explanation:

Given data:

Initial temperature = 273 K

Initial volume = 50.0 mL

Final temperature = 253 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

Charles Law

"The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure"

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

by putting values in formula,

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 50.0 mL × 253 K / 273 k

V₂ = 12650 mL.K / 273 K

V₂ = 46.34mL

let that person have a turn to speak : )

the answer is b because, investigating whether another species of moth also drinks tears might be interesting, but it would not directly explain why this species of moth does.

to explain why this species of moth drinks tears, the scientist could ask: "what nutrients that moths need are in elephant tears? "

the scientist could experiment with moth repellent or oter ways to keep the moths away, but that would not answer his original question.