Find the largest of three consecutive whole numbers such that twice the sum of the two smallest numbers is 13 more than three times the largest number.

17, 18, 19

Step-by-step explanation:

Let's say that the three consecutive numbers are

x-1,x,x+1.

Twice the sum of the two smallest numbers:

2(x -1 +x)

13 more than three times the largest number

13+3(x+1).

2(2x-1)=13+3x+3

4x-2=3x+16

4x-3x=16+2

x=18. So the numbers are:

17, 18, 19

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

a is the right answer