Using traditional methods, it takes 9.5 hours to receive a basic flying license. A new license training method using Computer Aided Instruction (CAI) has been proposed. A researcher used the technique with 15 students and observed that they had a mean of 10.0 hours with a standard deviation of 1.6. A level of significance of 0.1 will be used to determine if the technique performs differently than the traditional method. Assume the population distribution is approximately normal. Make the decision to reject or fail to reject the null hypothesis.

Step-by-step explanation:

Null hypothesis: u = 9.5hrs

Alternative: u =/ 9.5hrs

Using the t test

t = x-u/sd/√n

Where x is 10hrs, u is 9.5, sd is 1.6 and n is 15

t = 10-9.5 / (1.6/√15)

t = 0.5 / (0.4131)

t = 1.21

In order to make a conclusion, we have to find the p value at a significance level lot 0.1. The p value is 0.2263 which is greater than 0.1. This, we will fail to reject the null hypothesis and conclude that there is not enough statistical evidence to prove that the technique performs differently than the traditional method.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: