Find the equation of the line that passes through (3,-4) and is parallel to 3x+y+2=0 Leave your answer in the form y=mx+c

y = - 3x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

3x + y + 2 = 0 ( subtract 3x + 2 from both sides )

y = - 3x - 2 ← in slope- intercept form

with slope m = - 3

Parallel lines have equal slopes, thus

y = - 3x + c ← is the partial equation

To find c substitute (3, - 4) into the partial equation

- 4 = - 9 + c ⇒ c = - 4 + 9 = 5

y = - 3x + 5 ← equation of line in form y = mx + c

5y

step-by-step explanation:

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation: