A satellite dish is being designed so that it can pick up radio waves coming from space. The satellite dish will be in the shape of a parabola and will be positioned above the ground such that its focus is 50 ft above the ground. Using the ground as the x-axis, where should the base of the satellite be positioned? Which equation best describes the equation of the satellite? (0, 25); y = one over one hundredx2 − 25

(0, 50); y = one over two hundredx2 − 50

(0, 25); y = one over one hundredx2 + 25

(0, 50); y = one over two hundredx2 + 50

(0, 25); y = one over one hundredx2 + 25

Step-by-step explanation:

Let the ground be at (0,0). The base should be located at the midpoint between the ground and the focus (0,50). The position of the base of the satellite is:

The base (vertex) is at (0, 25).

A parabola can be described by the following general formula:

Where h = 0, k = 25 and a =50 -25 =25.

The equation for the parabola is:

Therefore, the answer is:

(0, 25); y = one over one hundredx2 + 25

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

wow ok so the answer is 1k or just k

because of combining like terms xd