A triangular-shaped deck has one side that is 4 feet longer than the shortest side and a third side that is 4 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 80 feet, what are the lengths of the three sides?

The length of three sides of the triangle are 20 feet, 24 feet  and 36 feet

Given :

Let 'x' be the shortest side of the triangle

one side that is 4 feet longer than the shortest side

so one side is 4 feet more than the shorter side

x+4

a third side that is 4 feet shorter than twice the length of the shortest side

third side is

Perimeter of the triangle is sum of all the three sides

Perimeter = x + (x+4)+(2x-4)

Given perimeter is 80 feet

The shortest side is 20 feet

One side is x+4= 20+4=24 feet

Largest side =

The length of three sides are 20 feet, 24 feet  and 36 feet

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The shortest side is 20 feet, the second side is 24 feet and the third side is 36 feet.

Step-by-step explanation:

Assuming that the shortest side of this triangle has a length of "x" feet, then one side is "x + 4" feet and the third is "2*x - 4" feet. Since the perimeter of the deck is 80 feet, then the sum of the length of these sides should be equal to that.

The shortest side is 20 feet, the second side is 24 feet and the third side is 36 feet.

2? if not the correct answer you might need to provide more information

step-by-step explanation: