Find all possible values of the digits Y, E, A, R if - EEE + AA - R = 1234, and different letters represent different digits.

Y=2, E=9, A=1, R=0

Step-by-step explanation:

starts from thousand

EEE starts from hundred

AA starts from tens

R is a units

So we can have

1000Y+100Y+10Y+Y-100E-10E-E+10A+A-R=1234

1111Y - 111E + 11A - R=1234

Y cannot be greater than 2 and it can't be 1 either because

if Y is 1, we will have a total of one thousand one hundred and eleven (1111) which is less than one thousand two hundred and thirty-four (1234) as from the answer in the question

So, it is safe to say Y=2 in order to have two thousand two hundred and twenty-two(2222)

This means that Y must be 2:

2222-111E+11A-R=1234

In this case, E would have to be 9 to make it possible for this to have a solution, by bringing it down to 1223.

-EEE

2222-999=1223

1223+11A-R=1234

1223+11=1234

This means that A must be 1 and that R must be 0.

2222

- 999

+11

-0

=1234

-6 is the correct option from the above given options