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Mathematics, 25.06.2020 02:01 wsdafvbhjkl

Sin2x= blank
A.1-2sin^2 x
B.2sin x cos x
C.1/2(cos(a-b)-cos(a+b))
D.2sinx + 2 cos x


Sin2x= blank 
A.1-2sin^2 x
B.2sin x cos x
C.1/2(cos(a-b)-cos(a+b))
D.2sinx + 2 cos x

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Answers: 3

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Sin2x= blank
A.1-2sin^2 x
B.2sin x cos x
C.1/2(cos(a-b)-cos(a+b))
D.2sinx +...
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