The function sequalsf(t) gives the position of a body moving on a coordinate line, with s in meters and t in seconds. Find the body's displacement and average velocity for the given time interval. sequals6t squaredplus3tplus5, 0 less than or equalsxless than or equals2

Δs=10m

5m/s

Step-by-step explanation:

s=t²+3t +5,0<=t<=2

Let f(t)=s=t²+3t +5

The displacement of the body over the time interval from 0 to 2 is

Δs=f(2)-f(0)

Δs=(2²+3(2) +5) - (0²+3(0) +5)

Δs=10m

The average velocity of the body over the time interval from 0 to 2 is

displacement / travel time =Δs/Δt

      =10 / 2

      =5m/s

c. (0.6,-1.4)

step-by-step explanation:

hope this

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative