Solve each problem
1)x-27=-(27-x)
2)6y-8=2(3y-4)
you in advance

1) x ∈ R

2) y ∈ R

Step-by-step explanation:

* Lets explain something very important when we solve an equation

 of one variable

- If we have an equation of x then the solution is one of these cases

# x has only one value

# x has no value

# x can be any value

- The first case when we solve for x and the answer is one value

- The second when x disappear and the left hand side of the

  equation not equal the right hand side

- The third when x disappear and the left hand side of the

  equation equal the right hand side

* Lets solve the problem

1)

∵ x - 27 = -(27 - x)

- Multiply the bracket (27 - x) by (-)

- Remember (-)(+) = (-) and (-)(-) = (+)

∴ x - 27 = -27 + x

- Subtract x from both sides and add 27 to both sides

∴ x - x = -27 + 27

∴ 0 = 0

∵ The left hand side = the right hand side

∴ x can be any real number

∴ x ∈ R ⇒ R is the set of real number

2)

∵ 6y - 8 = 2(3y - 4)

- Multiply the bracket (3y - 4) by 2

∴ 6y - 8 = 6y - 8

- Subtract 6y from both sides and add 8 to both sides

∴ 6y - 6y = -8 + 8

∴ 0 = 0

∵ The left hand side = the right hand side

∴ y can be any real number

∴ y ∈ R ⇒ R is the set of real number

don't give

take it once

try and try and you will not

happy to

pls mark as brainliest

step-by-step explanation:

the true ones are a b and d