y = –5x + 30 x = 10 What is the solution to the system of equations? (–20, 10) (10, –20) (10, 4) (4, 10)

(10, - 20 )

Step-by-step explanation:

Given the 2 equations

y = - 5x + 30 → (1)

x = 10 → (2)

Since the value of x is given substitute x = 10 into (1) for y

y = - 5(10) + 30 = - 50 + 30 = - 20

Solution is (10, - 20 )

(10, -20)

Step-by-step explanation:

y = –5x + 30

x = 10

x=10 ⇒ y= -5*10+30= -20

Then solution is (10, -20)

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square