2 Points A card game is being played and the 5 of spades, 9 of spades, and 9 of hearts

are drawn from a single deck. In order to win, the next card the player draws

from the deck must be higher than the highest card already drawn. What is

the probability that the next card the player draws is a winning card? (An ace

is considered to have a value of 1 and jacks, queens, and kings have a value

of 10.) Hint: A deck has 52 cards, 4 suits, and each suit has A, 2,3,4,5,6,7,8,

9,10,J, Q,K,

A. 25%

B. 24%

C. 32.6%

D. 8%

C) 32.6%

Step-by-step explanation:

Given:

Total number of cards = 52

3 Cards already drawn = 5 of spades, 9 of spades, and 9 of hearts.

To win the next card drawn must be greater than the highest card already drawn.

Required:

Find the probability of winning

Here, the highest card already drawn is 9 of spades or 9 of hearts.

The cards higher than 9 of spades or 9 of hearts are four in number (10, J, Q, K). Since, we have 4 suits, the highest cards remaining are 4 * 4 = 16.

Also, a total of 49 cards are remaining since 3 cards are already drawn (52 - 3 = 49).

Therefore, the probability that the next card the player draws is a winning card:

Convert to percentage:

0.326 * 100 = 32.6%

21/58.

hope to be marked brainliest

1010: 3030

is it i think