Mathematics, 11.06.2020 01:57 ash0470
A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 2. Column 2 is labeled f (x) with entries 4, 5, 6, 7. f (x) = x + 5 f (x) = x minus 5 f (x) = x + 1 f (x) = x minus 1
Answers: 3
Mathematics, 21.06.2019 14:30
In the image, point a marks the center of the circle. which two lengths must form a ratio of 1 : 2? (options are in the images since thought they were harmful phrases)
Answers: 1
Mathematics, 21.06.2019 19:50
Prove (a) cosh2(x) β sinh2(x) = 1 and (b) 1 β tanh 2(x) = sech 2(x). solution (a) cosh2(x) β sinh2(x) = ex + eβx 2 2 β 2 = e2x + 2 + eβ2x 4 β = 4 = . (b) we start with the identity proved in part (a): cosh2(x) β sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 β sinh2(x) cosh2(x) = 1 or 1 β tanh 2(x) = .
Answers: 3
Mathematics, 22.06.2019 00:00
Which of the following is the maximum value of the equation y=-x^2+2x+5 a. 5 b. 6 c. 2. d. 1
Answers: 1
A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 0, 1, 2. Column 2 is la...
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