An aquarium is designing a new exhibit to showcase clownfish and queen angelfish. The exhibit will hold a rectangular tank with length twice the size of the width, height is equal to 4 feet and total volume will equal to 500 cubic feet. What is a reasonable width of the tank to the nearest tenth of a foot?

The width of the tank is approximately 7.9 feet.

Step-by-step explanation:

The pool is a rectangular prism with the following dimensions:

length = 2*x feet

width = x feet

height = 4 feet

With volume equal to 500 cubic feet, therefore:

volume = length*width*height = 500

(2*x)*(x)*(4) = 500

8*x² = 500

x = sqrt(500 / 8)

x = sqrt(62.5)

x = 7.90569 feet

The width of the tank is 7.9 feet.

i'm not sure i quite understand, could you provide more information?

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.