Step-by-step explanation:
One solution :
         x = -1/12 = -0.083
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "1.2" was replaced by "(12/10)". 4 more similar replacement(s)
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
   (2/10)*(x-1)-(32/10)*x-((5/10)*(6*x+3)-(12/10))=0
Step by step solution :
Step  1  :
      6
Simplify  —
      5
Equation at the end of step  1  :
  2     32     5     6
 ((——•(x-1))-(——•x))-((——•(6x+3))-—)  = 0
  10     10    10     5
Step  2  :
      1
Simplify  —
      2
Equation at the end of step  2  :
  2     32    1     6
 ((——•(x-1))-(——•x))-((—•(6x+3))-—)  = 0
  10     10    2     5
Step  3  :
Step  4  :
Pulling out like terms :
4.1 Â Â Pull out like factors :
 6x + 3  =  3 • (2x + 1)
Equation at the end of step  4  :
  2     32    3•(2x+1) 6
 ((——•(x-1))-(——•x))-(————————-—)  = 0
  10     10     2   5
Step  5  :
Calculating the Least Common Multiple :
5.1 Â Â Find the Least Common Multiple
   The left denominator is :    2
   The right denominator is :    5
    Number of times each prime factor
    appears in the factorization of:
Prime
Factor  Left
Denominator  Right
Denominator  L.C.M = Max
{Left,Right}
2101
5011
Product of all
Prime Factors  2510
   Least Common Multiple:
   10
Calculating Multipliers :
5.2 Â Â Calculate multipliers for the two fractions
  Denote the Least Common Multiple by  L.C.M
  Denote the Left Multiplier by  Left_M
  Denote the Right Multiplier by  Right_M
  Denote the Left Deniminator by  L_Deno
  Denote the Right Multiplier by  R_Deno
 Left_M = L.C.M / L_Deno = 5
 Right_M = L.C.M / R_Deno = 2
Making Equivalent Fractions :
5.3 Â Â Â Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example :  1/2  and  2/4  are equivalent,  y/(y+1)2  and  (y2+y)/(y+1)3  are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
 L. Mult. • L. Num.    3 • (2x+1) • 5
 ——————————————————  =  ——————————————
    L.C.M          10   Â
 R. Mult. • R. Num.    6 • 2
 ——————————————————  =  —————
    L.C.M        10 Â
Adding fractions that have a common denominator :
5.4 Â Â Â Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
3 • (2x+1) • 5 - (6 • 2)   30x + 3
————————————————————————  =  ———————
      10          10 Â
Equation at the end of step  5  :
  2     32   (30x+3)
 ((——•(x-1))-(——•x))-———————  = 0
  10     10    10 Â
Step  6  :
      16
Simplify  ——
      5
Equation at the end of step  6  :
  2     16   (30x+3)
 ((——•(x-1))-(——•x))-———————  = 0
  10     5     10 Â
Step  7  :
      1
Simplify  —
      5
Equation at the end of step  7  :
  1        16x   (30x + 3)
 ((— • (x - 1)) -  ———) -  —————————  = 0
  5         5     10  Â
Step  8  :
Equation at the end of step  8  :
 (x - 1)   16x   (30x + 3)
 (——————— -  ———) -  —————————  = 0
   5     5     10  Â
Step  9  :
Adding fractions which have a common denominator :
9.1 Â Â Â Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
(x-1) - (16x) Â Â -15x - 1
—————————————  =  ————————
   5        5  Â
Equation at the end of step  9  :
 (-15x - 1)   (30x + 3)
 —————————— -  —————————  = 0
   5       10  Â
Step  10  :
Step  11  :
Pulling out like terms :
11.1 Â Â Pull out like factors :
 -15x - 1  =  -1 • (15x + 1)
Step  12  :
Pulling out like terms :
12.1 Â Â Pull out like factors :
 30x + 3  =  3 • (10x + 1)