A polynomial function has a root of –6 with multiplicity 1, a root of -2 with inultiplicity 3, a root of O with multiplicity 2. and a rool
of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph
is true?

The graph of the function is positive on (-6, -2).
The graph of the function is negative on (0, 0).
The graph of the function is positive on (-2, 4).
The graph of the function is negative on (4,co).

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation:

i believe the answer is d.

hope it you! : d

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

f(x) = y

f(-3) = -5

step-by-step explanation: