One rectangular solid with a square base has twice the height of another rectangular solid with a square base with
the same side length. Which statements about the two rectangular solids are true? Check all that apply.

The bases are congruent.

The solids are similar.

The ratio of the volumes of the first solid to the second solid is 8:1.

The volume of the first solid is twice as much as the volume of the second solid.

If the dimensions of the second solid are x by x by h, the first solid has 4xch more surface area than the second
solid.

70,000 + 6,000 + 800 + 30

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx