. The teacher decides that no student can win twice, so she removes the tickets of the first winner before drawing the second winner. What is the probability that she draws Kitzen first and then Ava second? Use a / to represent a fraction bar.

Step-by-step explanation:

The given table shows that there are 4 students, so there are 4 possible winner in total, but they have different number of tickets.

The total number of tickets is 48, that's the total possible outcomes. Kitzen has a probability of

Ava has a probability of

Now, the probability of having one event and the other is

Therefore, there is 8% probability of Kitzen winning first and Ava second.

(Notice that the probaility is not about Kitzen or Ava winning, it's about winning both, that's why the percentage is low)

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18