The function g is given in three equivalent forms. Which form most quickly reveals the zeros (or "roots") of the function?

g(x)=3(x+1)^2-12
g(x)=3(x+3)(x-1)
g(x)=3x^2+6x-9

g(x)=3(x+3)(x-1)

Step-by-step explanation:

g(x)=3(x+3)(x-1) is in factorized form, therefore it will easily reveal the zero's

simply putting it's factors equal to zero.

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step-by-step explanation:

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1