A population of 1200 rabbits increases by 2.5% each year. At the end of 5 years, there will be approximately 1,358 rabbits in the population. Which function can be used to determine the number of rabbits, y, in this population at the end of t years

y= 1200 (1.025)^t

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t  

Where:

p = original population

r = growing rate (decimal form)

t= years

A = population after t years

Replacing with the values given:

1200= 1200 (1+ 2.5/100)^5

1200= 1200 (1+ 0.025)^5

1200= 1200 (1.025)^5

For the number of rabbits, y, at the end of t years

y= 1200 (1.025)^t

Feel free to ask for more if needed or if you did not understand something.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.