(1 point) Find the z-score such that:
(a) The area under the standard normal curve to its left is 0.8164
z =
(b) The area under the standard normal curve to its left is 0.6192
z =
(c) The area under the standard normal curve to its right is 0.1941
z =
(d) The area under the standard normal curve to its right is 0.1055
z =

(a) The value of z is 0.90.

(b) The value of z is 0.30.

(c) The value of z is 0.86.

(d) The value of z is 1.25.

Step-by-step explanation:

If , then , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, .

(a)

Compute the value of z for P (Z < z) = 0.8164 as follows:

P (Z < z) = 0.8164

The probability is approximately true for z = 0.90.

Thus, the value of z is 0.90.

(b)

Compute the value of z for P (Z < z) = 0.6192 as follows:

P (Z < z) = 0.6192

The probability is approximately true for z = 0.30.

Thus, the value of z is 0.30.

(c)

Compute the value of z for P (Z > z) = 0.1941 as follows:

P (Z > z) = 0.1941

P (Z < z) = 1 - 0.1941

             = 0.8059

The probability is approximately true for z = 0.86.

Thus, the value of z is 0.86.

(d)

Compute the value of z for P (Z > z) = 0.1055 as follows:

P (Z > z) = 0.1055

P (Z < z) = 1 - 0.1055

             = 0.8945

The probability is approximately true for z = 1.25.

Thus, the value of z is 1.25.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841