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Mathematics, 05.05.2020 10:58 Brennen435

Solve (x + 2 < 5) ∩ (x - 7 > -6).

{x | 1 < x < 3}
{x | x < 3 or x > 1}
{all real numbers}

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Solve (x + 2 < 5) ∩ (x - 7 > -6).

{x | 1 < x < 3}
{x | x < 3 or x &...
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