A rock is thrown at an initial velocity of 80 feet per second.

Model this situation using a modification of the inequality from (see [ ]).

For what periods of time is the rock lower than 60 feet in the air?

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[A rock was thrown up into the air from the ground with an initial velocity of 64 feet per second.

The height of the rock can be described by the function (see picture) where t is the time in seconds and h is the height of the rock in feet.

For what period of time was the rock higher than 60 feet in the air?]

(This should be answered in one of my other posts.)
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too much is happening

Step-by-step explanation:

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.