The weight distribution of parcels sent in a certain manner is normal with mean of 12 lb and standard deviation of 3 lb. The parcel service wishes to establish a weight value c beyond which there will be a surcharge. What value of c is such that 99% of all parcels are under the surcharge weight?

21.16

Step-by-step explanation:

Starting from the theory we have the following equation:

Using the data supplied in the exercise, we have subtracting the mean and dividing by the standard deviation:

solving for "c", knowing that fi is a tabulating value:

therefore the value of c is equal to 21.16

6 on both sides and twelve on the top and the bottom

step-by-step explanation:

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3