How much wrapping paper would you need to cover a rectangular box that is 18.25 inches by 12 inches by 3 inches if you need 10% more wrapping paper than the surface area of the box? Give your answer to the nearest square inch.

  681 square inches

Step-by-step explanation:

The surface area of a rectangular prism of dimensions L, W, and H is given by ...

  A = 2(LW +H(L+W))

The surface area of the given box is ...

  A = 2(12·3 +18.25(12 +3)) = 2(36 +273.75) = 619.5 . . . square inches

The amount of wrapping paper required is 10% more than this value, so is ...

  paper required = (1 +.10)(619.5) = 681.45 ≈ 681 . . . square inches

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

a² + b²= c²

24² + 7² = c²

c= 25