Find the number that when added to the numerator and subtracted from the denominator of 3/11 results in a fraction equivalent to 5/2
Plz help thank you!!

7

Step-by-step explanation:

Suppose the "number" is x.

The problem says that when x is added to the numerator of 3/11 (in other words, added to 3) and subtracted from the denominator of 3/11 (in other words, subtracted from 11), the answer is 5/2. So:

(3 + x)/(11 - x) = 5/2

Cross-multiplying, we have:

2 * (3 + x) = 5 * (11 - x)

6 + 2x = 55 - 5x

7x = 55 - 6 = 49

x = 49/7 = 7

Thus, the answer is 7.

Hope this helps!

7

Step-by-step explanation:

Let that no. be b

(3+n)/(11-n) = 5/2

2(3+n) = 5(11-n)

6 + 2n = 55 - 5n

7n = 49

n = 7

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3