If you have 2 quadratics that are a system and the only point of intersection has a negative x value, how many solutions are there to the system?

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve