If T: (x, y) → (x + 3, y - 9), then T-1: (x, y) →.

A. (3 x, -9 y)
B. ( x - 3, y + 9)
C. ( x - 9, y + 3)
D. (-x/3 ,y/9 )

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

answer: 5

step-by-step explanation:

i don't see any

step-by-step explanation:

it is 570

step-by-step explanation: