Find the sum and product of the roots.
2x^2 + 6x - 8 = 0

A. sum = -7, product = 12
B. sum = -1/3 , product = -1/4
C. sum = -3, product = -4
D. sum = -1/3, product = -3/4

sum= -3 product=-4

Step-by-step explanation:

2x^2-2x+8x-8

2x(x-1)+8(x-1)

(2x+8)(x-1)

x=-4 x=1

answer: d. $20

step-by-step explanation:

just took the test

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐