A ball is thrown from a height of 32 meters with an initial downward velocity of 2/ms.
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Mathematics, 10.04.2020 08:48 SuBzErO24
A ball is thrown from a height of 32 meters with an initial downward velocity of 2/ms.
The ball's height h (in meters) after t seconds is given by the following.
h=−32−2t-5t^2
How long after the ball is thrown does it hit the ground? Round your answer(s) to the nearest hundredth.
Answers: 2
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