Students are asked to graph the inverse, f (x) of an absolute value function, f(x) after restricting its domain. The directions
also ask that the graph include a dashed line that can be used to verify that the functions are inverses of each other.
Which student's work is correct?

Please help!

The inverse of a graph is done by swapping the x and y coordinates.

The graph that illustrates the inverse of f(x) is graph d

From the graph of f(x), we have the following points;

The following transformation will be used to calculate the coordinates of the inverse function

So, the coordinates of the inverse function are:

Hence, the graph that illustrates the inverse of f(x) is graph d

See attachment for the graph of the inverse function.

Read more about inverse graphs at:

link

Pick the one in which inverse is a reflection of f(x) in the line y = x

(a,b) on f(x) maps onto (b,a) on its inverse.

Also, the graph of inverse should begin at (1,0) and pass through (5,4)

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

i dont have an answer

step-by-step explanation: