A bag contains 10 red marbles, 15 yellow marbles, 5 green marbles, and 20 blue marbles. Five marbles are drawn from the
bag.
What is the approximate probability that exactly two of the five are blue?

The approximate probability that exactly two of the five are blue is 0.3641

Step-by-step explanation:

Step 1

The total marble in the bag are

Step 2

When five marbles are drawn from the bag, we have to find the probability that exactly two of the five are blue.

=Probability that 2 blue marbles and 3 non blue marbles

Step 3

2 marbles should be drawn out of the 20 blue marbles and 3 non blue marbles out of 30 marbles

No of ways =

Total no of ways of drawing 5 marbles =

Probability=

Step 4

The approximate probability that exactly two of the five are blue is 0.3641

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: