A water bottle had the shape of a cylinder that is 22cm high with a 5 radius. The bottle is exactly half filled with water. What is the volume of the water in the bottle, rounded to the nearest tenth.

the volume of the water in the bottle is 863.5 cm³

Step-by-step explanation:

Since the water bottle is cylindrical, we would apply the formula for determining the volume of a cylinder which is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the water in the cylindrical bottle.

π is a constant whose value is 3.14

From the information given,

Radius = 5 cm

Height = 22/2 = 11 cm(because it is half full)

Therefore, the volume of the water in the bottle is

3.14 × 5² × 11

= 863.5 cm³

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )