You have two biased coins. Coin A comes up heads with probability 1/4. Coin B comes up heads with probability 3/4. However, you are not sure which is which, so you choose a coin randomly and you flip it. If the flip is heads, you guess that the flipped coin is B; otherwise, you guess that the flipped coin is A. What is the probability P[C] that your guess is correct

3/4

Step-by-step explanation:

Probability is the likelihood of an event.

No.of favourable outcomes/ Total no. of outcomes

Probability of coin selection : [Both coins have equal likelihood of being chosen]

Probability of head & tail by both coins :

Probability of getting head by Coin A : Prob (Coin A) & Prob (Head/CoinA)  = 1/2 x 1/4   = 1/8

Probability of getting tail by Coin A : Prob (Coin A) & Prob (Tail/CoinA) = 1/2 x 3/4 = 3/8

Probability of getting head by Coin B : Prob (Coin B) & Prob (Head/CoinB)  = 1/2 x 3/4   = 3/8

Probability of getting tail by Coin B : Prob (Coin B) & Prob (Head/CoinB)  = 1/2 x 1/4   = 1/8

Probability 'The guess [head from coin B, tail from coin A] :

Prob (Coin A) & Prob (Tail/CoinA) or Prob (Coin B) & Prob (Head/CoinB)  

= 3/8 + 3/8 = 3/4

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3