If the complex number x = 3 + bi and |x|2 = 13, which is the value of b?

b = 2

Step-by-step explanation:

We know that |x|² = 13 and x = 3+bi:

(3+bi)² = 13

3² + b² = 13

9 + b² = 13

Subtract 9 from each side:

9 + b² - 9 = 13 - 9

b² = 4

Take the square root of each side:

√b² = √4

b = 2

do i do it on a graph?

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.