A new version of the SAT is given to 1000 randomly selected high school seniors. The sample mean test score is 1110, and the sample standard deviation is 132. Construct a 95 % confidence interval for the population mean test score for high school seniors. Interpret the confidence interval

The 95 % confidence interval for the population mean test score for high school seniors is between 1101.8 and 1118.2. This means that we are 95% sure that the true population mean test score for high school seniors is between 1101.8 and 1118.2.

Step-by-step explanation:

Large sample size, so we can build a normal confidence interval.

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1110 - 8.2 = 1101.8.

The upper end of the interval is the sample mean added to M. So it is 1110 + 8.2 = 1118.2.

The 95 % confidence interval for the population mean test score for high school seniors is between 1101.8 and 1118.2. This means that we are 95% sure that the true population mean test score for high school seniors is between 1101.8 and 1118.2.

your answer is b ^w^ hope i

5/12, or 5: 12

step-by-step explanation: