A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 85% confidence interval for the mean and are assuming that the population standard deviation for the number of fast food meals consumed each week is 1.3. The study found that for a sample of 548 adults the mean number of fast food meals consumed per week is 5.6. Construct the desired confidence interval. Round your answers to one decimal place.

The 85% confidence interval for the mean is between 5.5 and 5.7 fast food meals consumed per week.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 5.6 - 0.08 = 5.52 = 5.5.

The upper end of the interval is the sample mean added to M. So it is 5.6 + 0.08 = 5.7.

The 85% confidence interval for the mean is between 5.5 and 5.7 fast food meals consumed per week.

what are the answear choices to the question.

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answer: need picture of problem

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