HCF 128, 192, and 80?

HCF = 2 × 2 × 2 × 2

= 16

Step-by-step explanation:

2 128 192 80

2 64 96 40

2 32 48 20

2 16 24 10

8 12 5

At this stage there is no common factor for the three numbers

HCF = 2 × 2 × 2 × 2

= 16

16

Step-by-step explanation:

Express each number as a product of it's prime factors

128 =

192 = × 3

80 = × 5

Identify those prime factors that the numbers have in common and multiply them.

The common factor of all 3 numbers is

HCF = = 16

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

x = 23.78

step-by-step explanation: