Mathematics, 12.03.2020 17:25 vicky10445
When they invest K dollars, a fishery can produce Q(K) pounds of fish per month, where Q(K) = 111 K1/3. In t months from now, their total investment will be K(t)=0.5t2+100 t +517 dollars. At what rate is the production of fish changing with respect to time 4 months from now? In 4 months from now, the fisher's production will be
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When they invest K dollars, a fishery can produce Q(K) pounds of fish per month, where Q(K) = 111 K1...
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