In how many different orders can the objects be manufactured if exactly one of the objects must be completed immediately before another

3628800

Missing Problem Statement:

A production line needs to manufacture 11 unique objects; and the order in which they're completed is important.

Step-by-step explanation:

One object must be completed immediately before another, which means that we can consider two objects in which one must be produced immediately before the other one, as one single unit, basically a pair.

Naming them object A and B, we can say

A and B must be produced one after another, so ,

AB being considered as one object and 9 other objects combined make total of 10 objects.

The different ways they can be manufactured = n!

Here n=10, since two objects A and B must be produced one after another.

The different ways they can be manufactured = n ! =10!=3628800

10

step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions