Tim has 7 magazines. He gave all of them to mike. Write a fraction that represents the part of the magazine tim gave to mike. Then write the fraction as a whole number.

Tim gave 7 / 7 = 1 (entire whole) part ie fraction of magazine to Mike

Part (Fraction) of portion given to other = Numerator / Denominator

=  Given / Total

So, fraction of magazines given by Tim to Mike = 7 / 7

Dividing it further as numerator = denominator , we get that Tim gave full 1 fraction to Mike

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First 7/7

Second 1

Step-by-step explanation:

Tim has 7 magazines and gave all of them (7), so he gave 7 out of 7 magazines: the fraction that corresponds to this is 7/7 (the number he gave over the total number he had). To know the whole number of this fraction, we just need to divide the numerator by the denominator, so 7 divided by 7 is 1.

1.677

step-by-step explanation:

i'm not good at explaining stuff but if you need an answer i'm here for you.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.