Solve the following system of equations. What is the x-value of the solution? 3x + 2y = 7 x - y + 1 = 0 2 4 0 1

x=1

Step-by-step explanation:

3x+2y=7

x-y+1=0

3x+2y=7

x-y=-1 /*2

3x+2y=7 (1)

2x-2y=-2 (2)

(1)+(2) 5x=5, x=5/5, x=1

x=1 y=2

(1,2)

Step-by-step explanation:

3x + 2y = 7

x - y + 1 = 0

Multiply the second equation by 2 so we can eliminate y

2(x - y + 1 )= 0*2

2x-2y+2 =0

Add this to the first equation

3x + 2y = 7

2x -2y +2 =0

5x +2 = 7

Subtract 2 from each side

5x+2-2=7-2

5x =5

Divide each side by 5

5x/5 =5/5

x=1

Now substitute into the second equation to find y

x - y + 1 = 0

1-y+1 =0

2-y =0

Add y to each side

2-y+y=0+y

2=y

is this part of a question or something