Suppose you have gone bowling with an excellent player who bowls a strike (i. e. when they hit all of the pins) 73% of the time. By the fourth frame, this person realizes that they can clinch first place in a local tournament by bowling 3 consecutive strikes. What is the likelihood of this happening

The probability of bowling 3 consecutive strikes is 0.3890.

Explanation:

On any given turn, this player has a 73% chance of bowling a strike. Hence:

Probability of bowling a strike = P(S) = 73% = 0.73

We need to find the probability of this player bowling 3 consecutive strikes. This is computed as follows:

Probability of bowling 3 consecutive strikes

= Probability of bowling first strike x Probability of bowling second strike x Probability of bowling third strike

= P(S) x P(S) x P(S)

= 0.73 x 0.73 x 0.73

= 0.3890

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this