Find the coordinates of the point of intersection of the two lines 2x-7y= 2 and 4x+5y=42

x = 8, y = 2

Step-by-step explanation:

2x - 7y = 2 (1)

4x + 5y = 42 (2)

2x = 2 + 7y (1)

2(2 + 7y) + 5y = 42 (2)

4 + 14y + 5y = 42

19y = 38

y = 2

2x = 2 + 7(2) = 16

x = 8

(8, 2 )

Step-by-step explanation:

Given the 2 equations

2x - 7y = 2 → (1)

4x + 5y = 42 → (2)

Multiplying (1) by - 2 and adding to (2) will eliminate the term in x

- 4x + 14y = - 4 → (3)

Add (2) and (3) term by term

19y = 38 ( divide both sides by 19 )

y = 2

Substitute y = 2 into either of the 2 equations and solve for y

Substituting y = 2 into (2)

4x + 5(2) = 42

4x + 10 = 42 ( subtract 10 from both sides )

4x = 32 ( divide both sides by 4 )

x = 8

Thus point of intersection = (8, 2 )

answer: sine

step-by-step explanation:

one set of data has more variation than the other. hope this !