Arectangular poster has an ares of 190 inches squared. the height of the poster is one inch less than twice its width. find the dimension of the poster. show all work

Area= 190
height= 2(width) - 1

area= length times width
190= (2(width) -1) x width
190 = 2w^2-w
w^2-w-190 = 0

use quadratic fomula, you'll get w= 10

so height will be 2(10)-1 = 19 

C. i believe it is (5×(-20))+(100×(0.7))