A highway safety council reported that there were fatalities among drivers in auto accidents in a particular year. Following is a frequency distribution of their ages.
Approximate the mean age. Round your answer to one decimal place.

Age Number of Fatalities
11-20 338
21-30 1562
31-40 856
41-50 668
51-60 428
61-70 109

34.5

Step-by-step explanation:

Mean age can be computed as

xbar=sum(fx)/sumf

x can be computed by computing midpoints for each class.

Age      Midpoint (x)

11-20      [11+20]/2=15.5

21-30     [21+30]/2=25.5

31-40     [31+40]/2=35.5

41-50     [41+50]/2=45.5

51-60     [51+60]/2=55.5

61-70     [61+70]/2=65.5

Age      Midpoint(x)   Number of Fatalities (f)   fx

11-20           15.5               338                            5239

21-30          25.5              1562                           39831

31-40          35.5               856                           30388

41-50          45.5              668                           30394

51-60          55.5              428                           23754

61-70          65.5               109                           7139.5

sumfx=5239+39831+30388+30394+23754+7139.5=136745.5

sumf=338+1562+856+668+428+109=3961

xbar=136745.5/3961

xbar=34.5

The approximate mean age is 34.5.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.